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The mean of 50 observations is 36

SpletThe sum of all the 50 observations = 36 × 50 = 1800. Hence, the sum of remaining 48 observations = 1800- 42- 30 = 1728 = 48 × 36. So, the mean of remaining 48 observations … Splet26. mar. 2024 · σ x ¯ = ∑ x ¯ 2 P ( x ¯) − μ x ¯ 2 = 24, 974 − 158 2 = 10. The mean and standard deviation of the population { 152, 156, 160, 164 } in the example are μ = 158 and σ = 20. The mean of the sample mean X ¯ that we have just computed is exactly the mean of the population. The standard deviation of the sample mean X ¯ that we have ...

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SpletOut of these observations if the mean of first 13 observations is 32 and that of the last 13 observations is 40, the 13th observation is : a. 23 b. 36 c. 38 d. 40. Solution: It is given that. Mean of 25 observations = 36. Sum of 25 observations = 36 × 25 = 900. Mean of first 13 observations = 32. Sum of first 13 observations = 13 × 32 = 416 ... Splet07. jul. 2024 · The mean of 50 observations is 36. If two observations 30 and 42 are deleted, then the mean of the remaining observations is Updated On: Jul 7, 2024 48 36 38 none of these Correct Answer: B Solution and Explanation The sum of all the 50 observations = 36 \times × 50 = 1800. how high should a shower curtain be https://adoptiondiscussions.com

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Splet30. nov. 2024 · the mean of 50 observations is 36. if two observations 30 and 42 are deleted, then the mean of the remaining observations is See answer Advertisement … SpletA sample of 36 observations is selected from a normal population. The sample mean is 21, and the population standard deviation is 5. Conduct the following test of hypothesis using the .05 significance level. H_0:μ≤20; H_1:μ>20 H 0: μ ≤ 20;H 1: μ > 20 Solutions Verified Solution A Solution B Create an account to view solutions SpletThe mean of 50 observations = 36. Formula: Average = sum of all observations/Total number of all observations. Calculation: Mean of 50 observations = 36. Sum of 50 observations = 36 × 50 = 1800. Correct sum of 50 observations = 1800 - 23 + 48 = 1825. Correct mean of 50 observations = 1825/50 = 36.5. Short Trick: how high should a shower niche be installed

The mean of 50 observations was 36. It was found later that an ...

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The mean of 50 observations is 36

the mean of 50 observations is 36. if two observations 30 and 42 …

SpletThe average of 50 observations= 36 The average of 30 & 42= (30+42)/2= 36 Since the average of the two excluded observations is also 36, the average of the remaining observations also will not be altered. It will be the same 36. OK SpletCorrect option is A) Let u=36 be the mean of 50 observations. ∴u×50=x 1+x 2.....+x 50. Now two observations 30 and 42 are deleted. So, sum of remaining …

The mean of 50 observations is 36

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Splet09. jun. 2024 · The mean and standard deviation of 50 observations are 15 and 2 respectively. It was found that one incorrect observation was taken such that the sum of correct and incorrect observations is 70. If the correct mean is 16, then the correct variance is equal to : A 10 B 36 C 43 D 60 Check Answer 2 JEE Main 2024 (Online) 26th June … SpletThe mean of 100 observations is 50. If one of the observations which was 50 is replaced by 150, the resulting will be (a) 50.5 (b) 51 (c) 51.5 (d) 52. Q. The mean of 100 observations is 50. If one of the observations, 50 is replaced by 150, what is the resulting mean? Q.

Splet10. apr. 2024 · View solution. Question Text. Out of 50 observations the mean of 25 observations is 30 and mean of rest 25 observation is 32 , Then mean of 50 observation … SpletThe mean and standard deviation of 50 observations are 15 and 2 respectively. It was found that one incorrect observation was taken such that the sum of correct and incorrect observations is 70. If the correct mean is 16, then the correct variance is equal to 43. Explanation: Number of observations are = 50. Mean `(barx)` = 15. Standard ...

SpletTranscribed Image Text: A random sample of n = 36 observations is drawn from a population with a mean equal to 15 and a standard deviation equal to 6. Complete parts a through g below. a. Give the mean and standard deviation of the (repeated) sampling distribution x. x = ox (Type integers or decimals.) b. SpletThe mean of 50 observations is 36 . If its two observations 30 and 42 are deleted, then theW mean of the remaining observations is-(1) 48(2) 36(3) 38(4) none...

Splet01. apr. 2024 · Question. Question asked by Filo student. The mean of 100 observations is 50 . If one of the observations which was 50 is replaced by 40 , the resulting mean will be: (N.D.A. 1991) 50. 49.90.

SpletQuestion The mean of 50 observations is 36. If its two observations 30 and 42 are deleted, then the mean of the remaining observations is A 48 B 36 C 38 D none of these Medium … high fibre diet paedSplet627 Likes, 36 Comments - Sanjog shrestha ©️ (@existing_as_nature) on Instagram: "Day 6: 23 March 2024: Decided to go for a hike up the snow hill before the sunset to Khaptad … how high should a tennis net be at the centerSplet07. jul. 2024 · none of these Correct Answer: B Solution and Explanation The sum of all the 50 observations = 36 \times × 50 = 1800. Hence, the sum of remaining 48 observations = … how high should a shower niche behow high should a shower head beSpletAnswer (1 of 3): 50 observations sum/50=36 50 observation sum=50*36=1800 Then 48 taken wrongly as 23 48–23=25 Then real sum of 50 observation=1800+25=1825 Then … how high should a step beSpletThe mean of 25 observations is 36. Out of these observations if the mean of first 13 observations is 32 and that the last 13 observations is 40, the 13 th observations is (a) … high fibre dog food canadaSplet19. avg. 2024 · The mean of 50 observation is 36. if two observation 30 and 42 are to be excluded, then the mena of the reamining observations will be- A. 36 B. 38 C. 48 D. 50. ... how high should a step up box be