NettetQuestion: Evaluate integral^L_-L sin^2 (n pi x/L) dx and ntegral^L_-L cos^2 (npix/L)dx. Show transcribed image text. Expert Answer. Who are the experts? Experts are tested by Chegg as specialists in their subject area. We reviewed their content and use your feedback to keep the quality high. NettetFind the integral of y = f (x) = sin (npix/l) dx (sinus of (n Pi x divide by l)) - with detailed solution [THERE'S THE ANSWER!] online Solving integrals / sin (npix/l) Integral of …
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NettetDetailed step by step solution for integral of cos((npix)/L)sin((npix)/L) Solutions Graphing Practice; New Geometry; Calculators; Notebook . Groups Cheat Sheets. Sign in; … NettetWhen you do the integral you have twice as much positive area as negative area, so you don't get zero for an answer. Conclusion: if m is not an integer then the integral is not zero. If you change the limits of the integral to be something other than a full period (2pi), the integral comes out NOT zero. ban muon hen ho viet kieu my
Solve ∫ sin(npix) wrt x Microsoft Math Solver
Nettet$$\int \frac{l}{2} \sin{\left(\frac{x \pi n}{l} \right)}\, dx = C + \frac{l \left(\begin{cases} 0 & \text{for}\: n = 0 \\- \frac{l \cos{\left(\frac{x \pi n}{l} \right ... Nettet∫ 0 L cos ( ( n + m) π x L) d x = L ( n + m) π sin ( ( n + m) π x L) x = 0 L = L ( n + m) π sin ( ( n + m) π) = 0 since sin ( k π) = 0 for any integer k. Share Cite answered Dec 11, 2015 at 22:03 user169852 Add a comment 1 Well, since you said n = m your integral reduces to ∫ 0 L 1 − cos ( 2 π n x L) d x which is L − L sin ( 2 n π) 2 n π = L Nettet∫ cos (mpix/L)cos (npix/L) dx = ∫ sin (mpix/L)sin (npix/L) dx = Ldelta_ {m n} where Ldelta_ {m n} is a function that is 1 if m=n and 0 otherwise. Reply 1 17 years ago A just calculate the integrals! Reply 2 17 years ago A I will try to make my answer even more helpful than kikzen's! Use 2cos (A)cos (B) = cos (A + B) + cos (A - B) ban muon hen ho tap 856