WebFeb 19, 2024 · Best answer Given: ∠OBD = 50° Here, AB and CD are the diameters of the circles with centre O. ∠DBC = 90° …. (i) [Angle in the semi-circle] Also, ∠DBC = 50° + ∠OBC 90° = 50° + ∠OBC or ∠OBC = 40° Again, By degree measure theorem: ∠AOC = 2 ∠ABC ∠AOC = 2∠OBC = 2 x 40° = 80° ← Prev Question Next Question → Find MCQs & Mock Test JEE … WebSolution: In triangle OAB OA = OB ( radius of a circle) ∠OAB = ∠OBA ∠OBA = 40º (angles opposite to equal sides are equal) Using the angle sum property ∠AOB + ∠OBA + ∠BAO = 180º Substituting the values ∠AOB + 40º + 40º = 180º By further calculation ∠AOB + 80º = 180º ∠AOB = 180º - 80º ∠AOB = 100º

In the figure, O is the centre of the circle. If ∠ OBC =25∘, then ∠ …

WebIf ∠ OBC = 25 ∘, then ∠ BAC in degree is equal to: A 25 B 30 C 65 D 150 Solution The correct option is D 65 OB=OC [radii of the same circle] ∠ OCB= ∠ OBC=25 ∘ [angles opposite to equal sides of a triangle] So, ∠ BOC = [180 ∘ - (25 ∘ +25 ∘ )] = 130 ∘ ∴ ∠ BAC = 1 2 × ∠ BOC = 65 ∘ WebIn figure, if ∠ABC = 20°, then ∠AOC is equal to (a) 20° (b) 40° (c) 60° (d) 10° Thinking Process Use the theorem, that in a circale the angle subtended by an arc at the centre is … here is a summary of our discussion

In the Given Figure, If ∠Abc = 45°, Then ∠Aoc = - Mathematics

WebAug 19, 2024 · ∠ABC = 20° We know that, “The angle subtended by an arc at the center of a circle is twice the angle subtended by it at remaining part of the circle” According to the … WebIf figure, if`angleABC=20^ (@),\"then\"angleAOC\" is equal to\"`. Doubtnut. 2.63M subscribers. Subscribe. 3.3K views 3 years ago. WebSolution 90° We have to find ∠AOC. As we know that the angle subtended by an arc of a circle at the centre is double the angle subtended by it at any point on the remaining part of the circle. ∠ A O C = 2 ∠ A B C = 2 × 45 = 90° matthewschmidtmd.com